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这是一个创建于 3061 天前的主题，其中的信息可能已经有所发展或是发生改变。
最近开始学 python ，以前没怎么接触编程，就大二的时候有学过 vb 。
----------------------------------------------------------------------------------------------------------------------------------------------
def number_generator():
n = 11
while True:
yield n
n = n + 1
def palindrome_check(n):
string = str(n)
return string[0] == string[::-1]
def next_number():
it = number_generator()
while True:
n = next(it)
yield n
it = filter(palindrome_check(n), it)
for a in next_number():
if a < 1000:
print(a)
else:
break
----------------------------------------------------------------------------------------------------------------------------------------------
这是判断回数的代码，但是一直出错
----------------------------------------------------------------------------------------------------------------------------------------------
Traceback (most recent call last):
File "C:/Users/Administrator/AppData/Local/Programs/Python/Python35-32/HH.py", line 21, in <module>
for a in huishu():
File "C:/Users/Administrator/AppData/Local/Programs/Python/Python35-32/HH.py", line 16, in huishu
n = next(it)
TypeError: 'bool' object is not callable
----------------------------------------------------------------------------------------------------------------------------------------------请问问题在哪啊（为什么没排版？？？？？？）
----------------------------------------------------------------------------------------------------------------------------------------------
def number_generator():
n = 11
while True:
yield n
n = n + 1
def palindrome_check(n):
string = str(n)
return string[0] == string[::-1]
def next_number():
it = number_generator()
while True:
n = next(it)
yield n
it = filter(palindrome_check(n), it)
for a in next_number():
if a < 1000:
print(a)
else:
break
----------------------------------------------------------------------------------------------------------------------------------------------
这是判断回数的代码，但是一直出错
----------------------------------------------------------------------------------------------------------------------------------------------
Traceback (most recent call last):
File "C:/Users/Administrator/AppData/Local/Programs/Python/Python35-32/HH.py", line 21, in <module>
for a in huishu():
File "C:/Users/Administrator/AppData/Local/Programs/Python/Python35-32/HH.py", line 16, in huishu
n = next(it)
TypeError: 'bool' object is not callable
----------------------------------------------------------------------------------------------------------------------------------------------请问问题在哪啊（为什么没排版？？？？？？）
第 1 条附言 · 2016-08-11 11:54:10 +08:00
有一个错误，应该这样
def palindrome_check(n):
string = str(n)
return string == string[::-1]
def palindrome_check(n):
string = str(n)
return string == string[::-1]
 |
1
gotounix 2016-08-11 11:40:29 +08:00
next_number 函数中
it = filter(palindrome_check, it) |
 |
3
mgna17 2016-08-11 12:01:11 +08:00
发帖的时候右下角选 markdown
代码这样贴： ``` 你的代码 ``` |
 |
5
hitmanx 2016-08-11 12:08:07 +08:00 via iPhone
Filter 的第一个变量应该传个函数指针，你传的的是个函数调用，类型相当于是它的返回值，是 bool 的，所以说 bool not callable 。另外你是不是忘了把 int 转成 str 了，当调用 palindrome 时
|
 |
7
lll9p 2016-08-11 12:57:32 +08:00
```
def number_generator(): n = 11 while True: yield n n = n + 1 def palindrome_check(n): string = str(n) # .... return string == string[::-1] def next_number(): it = number_generator() while True: n = next(it) yield n # .... it = filter(palindrome_check, it) for a in next_number(): if a < 1000: print(a) else: break ``` |
|
8
lll9p 2016-08-11 12:58:35 +08:00
palindrome_check 不是应该用 string == string[::-1] 来判断的吗
还有应该写成这样 filter(palindrome_check, it) |
 |
9
getlost OP |
 |
11
aitaii 2016-08-11 18:36:05 +08:00
``` python
def palindrome_check(n): string = str(n) return string == string[::-1] ``` |
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